Read a XML file in Go

Golang has a very powerful encoding/xml package that comes with the standard library. All you need to do is the create the data structures to map according to XML document. In this tutorial we will learn how to read this XML document with the xml.Unmarshal() function Employee.xml <?xml version="1.0"?> <company> <staff> <id>101</id> <firstname>Derek</firstname> <lastname>Young</lastname> <username>derekyoung</username> </staff> <staff> <id>102</id> <firstname>John</firstname> <lastname>Smith</lastname> <username>johnsmith</username> </staff> </company> and map to these data structs and print out the values type Staff struct { XMLName xml.Name `xml:"staff"` ID int `xml:"id"` FirstName string `xml:"firstname"` LastName string `xml:"lastname"` UserName string `xml:"username"` type Company struct { XMLName xml.Name `xml:"company"` Staffs []Staff `xml:"staff"` In real life, a company has many staffs. Therefore, we map Company.Staffs to Staff struct. With the data structures defined. We are going to use the xml.Unmarshal() function to load the XML data into the Company structure. var c Company xml.Unmarshal(XMLdata, &c) Below is the full code of reading the XML file Employees.xml package main import ( "fmt" "io/ioutil" "os" "encoding/xml" ) type Staff struct { XMLName xml.Name `xml:"staff"` ID int `xml:"id"` FirstName string `xml:"firstname"` LastName string `xml:"lastname"` UserName string `xml:"username"` type Company struct { XMLName xml.Name `xml:"company"` Staffs []Staff `xml:"staff"` func (s Staff) String() string { return fmt.Sprintf("\t ID : %d - FirstName : %s - LastName : %s - UserName : %s \n", s.ID, s.FirstName , s.LastName, s.UserName) func main() { xmlFile, err := os.Open("Employees.xml") if err != nil { fmt.Println("Error opening file:", err) return defer xmlFile.Close() XMLdata, _ := ioutil.ReadAll(xmlFile) var c Company xml.Unmarshal(XMLdata, &c) fmt.Println(c.Staffs) and the output after parsing. go run parseEmployee.go ID : 101 - FirstName : Derek - LastName : Young - UserName : derekyoung ID : 102 - FirstName : John - LastName : Smith - UserName : johnsmith Hope this tutorial is helpful enough to you. Please leave your comment below if you have any question.