Golang : Convert int(year) to time.Time type
Problem :
You have integer value such as a year and you want to convert the integer to time.Time type. How to do that?
Solution :
Parse the integer with time.Date()
function and return the time.Time type
package main
import (
"fmt"
"time"
)
func YearTime(y int) time.Time {
// convert int to Time - use the last day of the year, which is 31st December
t := time.Date(y, time.December, 31, 0, 0, 0, 0, time.Local)
return t
}
func main() {
yTime := YearTime(2015)
fmt.Println("Year is : ", yTime.Year())
}
Output :
Year is : 2015
Reference :
By Adam Ng
IF you gain some knowledge or the information here solved your programming problem. Please consider donating to the less fortunate or some charities that you like. Apart from donation, planting trees, volunteering or reducing your carbon footprint will be great too.
Advertisement
Tutorials
+4.7k Random number generation with crypto/rand in Go
+6.9k Golang : Encrypt and decrypt data with x509 crypto
+20.9k Golang : Math pow(the power of x^y) example
+6.1k Golang : Setting variable value with ldflags
+16.9k Golang : Find biggest/largest number in array
+2.3k HTTP common errors and their meaning explained
+6.4k Golang : Removes punctuation or defined delimiter from the user's input
+29.4k Golang : convert(cast) bytes to string
+38.7k Golang : How to convert character to ASCII and back
+3.4k WARNING: UNPROTECTED PRIVATE KEY FILE! error message
+2.7k nginx : force all pages to be SSL
+5.3k Golang : Random integer with rand.Seed() within a given range