Golang : Convert(cast) string to uint8 type and back to string

Problem :

You have a variable of type string and you want to convert/type cast it to uint8 type.

Solution :

If you plan to convert a single character, then type cast it with uint8() function. If the string is couple of characters, use []uint8() instead.

For example :

 package main

 import (
  "fmt"
  "reflect"
 )

 var str string = "this is a string"

 func main() {
  fmt.Printf("The value of test is %s \n", str)
  fmt.Printf("The type of test is %v \n", reflect.TypeOf(str))

  newStr := []uint8(str)

  fmt.Printf("The value of newStr is %s \n", newStr)
  fmt.Printf("The type of newStr is %v \n", reflect.TypeOf(newStr))

  // convert back to string
  backToStr := string([]byte(newStr[:]))
  
  fmt.Println(backToStr)
  
  fmt.Printf("The value of backToStr is [%s] \n", backToStr)
  fmt.Printf("The type of backToStr is %v \n", reflect.TypeOf(backToStr))

 }

Output :

The value of test is this is a string

The type of test is string

The value of newStr is this is a string

The type of newStr is []uint8

this is a string

The value of backToStr is [this is a string]

The type of backToStr is string