Golang : Strings comparison




Given that mostly backend services deal with text data. There bound to be times when there is a need to compare strings. So how does one compare strings in Golang? After digging around....finally found out that the strings.EqualFold function can be used to compare strings (case insensitive)

For example :

 package main

 import (
 "fmt"
 "strings"
 )

 func main() {

 string1 := "Hello"
 string2 := "World"
 string3 := "HELLo"

 // true
 bool1 := strings.EqualFold(string1, string1)

 // false
 bool2 := strings.EqualFold(string1, string2)

 // true
 bool3 := strings.EqualFold(string1, string3)

 fmt.Printf("%s is equal to %s : %v \n", string1, string1, bool1)

 fmt.Printf("%s is equal to %s : %v \n", string1, string2, bool2)

 // EqualFold comparison is case IN-sensitive
 fmt.Printf("%s is equal to %s : %v \n", string1, string3, bool3)

 }

Output :

Hello is equal to Hello : true

Hello is equal to World : false

Hello is equal to HELLo : true

Reference :

http://golang.org/pkg/strings/#EqualFold

  See also : Golang : Regular Expression find string example





By Adam Ng

IF you gain some knowledge or the information here solved your programming problem. Please consider donating to the less fortunate or some charities that you like. Apart from donation, planting trees, volunteering or reducing your carbon footprint will be great too.


Advertisement