Golang : Find commonalities in two slices or arrays example
Problem:
You have two slices of the same length and you want to find out if they have similar/common items.
Solution :
- Iterate items of the first slice.
- Get the index number.
- Use the index number to get the second slice item.
- Compare the items.
- If similar or common, then add the item to a new slice.
- Loop until no more item in the first slice.
Here you go!
package main
import (
"fmt"
)
// NOTE : This example will only work if the length of slice a == length of slice b
// In production, make sure to check the length and capacity of the slices
// before comparing.
func main() {
a := []string{"Hello", "No", "Cheers"}
fmt.Println("Slice a : ", a)
b := []string{"Hello", "Yes", "Cheers"}
fmt.Println("Slice b : ", b)
// compare a to be and find common items
// and store into c
c := []string{}
for i := range a {
if a[i] == b[i] {
c = append(c, a[i])
}
}
fmt.Println("Common items : ", c)
// compare a to be and find item not in a
// and store into d
d := []string{}
for i := range a {
if a[i] != b[i] {
d = append(d, a[i])
}
}
fmt.Println("Item that a has over b ", d)
// compare a to be and find item not in b
// and store into e
e := []string{}
for i := range b { // iterate b instead of a
if a[i] != b[i] {
e = append(e, b[i])
}
}
fmt.Println("Item that b has over a ", e)
}
Output :
Slice a : [Hello No Cheers]
Slice b : [Hello Yes Cheers]
Common items : [Hello Cheers]
Item that a has over b [No]
Item that b has over a [Yes]
NOTES: This example will only work if the length of slice a == length of slice b. In production, make sure to check the length and capacity of the slices before comparing.Otherwise, you will get panic: runtime error: index out of range
error.
References :
See also : Golang : How to count duplicate items in slice/array?
By Adam Ng
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