Golang : Convert IP version 6 address to integer or decimal number
Problem :
You have IP address version 6 in string format and you want to convert it into integer. How to do that?
NOTE : IP address in decimal number format is easier to search, filter or compare. For example, searching for IP address in a given range.
Solution :
Use math/big.Int.SetBytes()
to convert the IPv6 address to a signed multi-precision integer.
package main
import (
"fmt"
"math/big"
"net"
)
func IP6toInt(IPv6Address net.IP) *big.Int {
IPv6Int := big.NewInt(0)
// from http://golang.org/pkg/net/#pkg-constants
// IPv6len = 16
IPv6Int.SetBytes(IPv6Address.To16())
return IPv6Int
}
func main() {
ipv6Decimal := IP6toInt(net.ParseIP("FE80::0202:B3FF:FE1E:8329"))
fmt.Println(ipv6Decimal)
}
Output :
338288524927261089654163772891438416681
References :
By Adam Ng
IF you gain some knowledge or the information here solved your programming problem. Please consider donating to the less fortunate or some charities that you like. Apart from donation, planting trees, volunteering or reducing your carbon footprint will be great too.
Advertisement
Tutorials
+25k Golang : Convert file content into array of bytes
+20.8k Golang : Securing password with salt
+17.1k Golang : Implement getters and setters
+8.7k Golang : Sort and reverse sort a slice of integers
+9k Golang : Random Rune generator
+10.5k Golang : Get remaining text such as id or filename after last segment in URL path
+5k Fontello : How to load and use fonts?
+4.7k Javascript : How to refresh page with JQuery ?
+6.2k Golang : Of hash table and hash map
+53.2k Golang : Unmarshal JSON from http response
+7.3k Golang : How to check if input string is a word?